Question

think about the process. the length of cell a is (6\times10^{-6} m). the length of cell b is (0.000002 m). what is the ratio of cell as length to cell bs length? use pencil and paper. is it easier to find the ratio when the numbers are expressed in scientific - notation, standard notation or a different form? explain your reasoning.
the ratio of cell as length to cell bs length is (square).
(type the ratio as a simplified fraction.)

Explanation:

Step1: Write length of B in scientific - notation

The length of $B = 0.000002m=2\times10^{- 6}m$.

Step2: Calculate the ratio

The ratio of the length of $A$ to the length of $B$ is $\frac{6\times10^{-4}}{2\times10^{-6}}$.
Using the rule of exponents $\frac{a^m}{a^n}=a^{m - n}$, we have $\frac{6}{2}\times10^{-4-(-6)} = 3\times10^{2}$.
In fraction form, $3\times10^{2}=\frac{300}{1}$.

Answer:

$\frac{300}{1}$