Question

e ticket
complete the questions below. show your work!

1. expand and simplify.

a) $4(x - 5)$
$4x-20$
b) $(2x^{3} - 5x) - (3x^{3} - 2x^{2} + 7x)$
$2x^{3}-5x - 3x^{3}+2x^{2}-7x$
$2x^{3}- 3x^{3} +2x^{2}-5x-7x$
$-x^{3} +2x^{2}-12x$

Explanation:

Step1: Distribute 4 to terms inside parentheses

$4(x - 5) = 4x - 4\times5$

Step2: Calculate the constant term

$4x - 20$

Step1: Distribute the negative sign

$(2x^3 - 5x) - (3x^3 - 2x^2 + 7x) = 2x^3 - 5x - 3x^3 + 2x^2 - 7x$

Step2: Combine like cubic terms

$2x^3 - 3x^3 = -x^3$

Step3: Bring down the quadratic term

$-x^3 + 2x^2$

Step4: Combine like linear terms

$-5x - 7x = -12x$

Step5: Combine all simplified terms

$-x^3 + 2x^2 - 12x$

Answer:

a) $4x - 20$
b) $-x^3 + 2x^2 - 12x$