Question

(3) in a time of 2.5 minutes michael walks 150 m to the south and then turns around and walks 225 meters to the north. what are michaels average speed and average velocity?

Explanation:

Step1: Convert time to seconds

$t = 2.5\times60s= 150s$

Step2: Calculate total distance for average - speed

The total distance $d$ is the sum of the distances walked. $d=150 + 225=375m$. The formula for average speed $v_{avg - speed}=\frac{d}{t}$. Substituting the values, we get $v_{avg - speed}=\frac{375}{150}=2.5m/s$.

Step3: Calculate displacement for average - velocity

Displacement $\Delta x$ is the final position minus the initial position. He walks 150m south and 225m north. So, $\Delta x=225 - 150 = 75m$ (north). The formula for average velocity $v_{avg - velocity}=\frac{\Delta x}{t}$. Substituting the values, we get $v_{avg - velocity}=\frac{75}{150}=0.5m/s$ (north).

Answer:

Average speed: $2.5m/s$; Average velocity: $0.5m/s$ (north)