Question

if a town with a population of 8,380 doubles in size every 77 years, what will the population be 462 years from now? people submit

Explanation:

Step1: Find the number of doubling periods

To find how many times the population doubles in 462 years, divide the total years by the time per doubling period. The formula is $\text{Number of periods} = \frac{462}{77}$.
Calculating, $\frac{462}{77} = 6$.

Step2: Calculate the final population

The population doubles each period, so after $n$ periods, the population is $P = P_0 \times 2^n$, where $P_0 = 8380$ and $n = 6$.
So $P = 8380 \times 2^6$.
First, calculate $2^6 = 64$.
Then, $8380 \times 64 = 536320$.

Answer:

536320