Question

translate quadrilateral adcb 5 units to the left and 2 units down. what are the coordinates of new quadrilateral adcb? (1 point) o a(-1,0), d(-1,5), c(4,2), b(2,-1) o a(-1,-4), d(-1,1), c(4,-2), b(2,-5) o a(0,0), d(9,5), c(13,2), b(12,-1) o a(9,-1), d(9,1), c(13,-2), b(12,-5)

Explanation:

Step1: Identify original coordinates

The original coordinates are \(A(4, - 2)\), \(B(7,-3)\), \(C(9,0)\), \(D(4,3)\).

Step2: Apply left - translation rule

To move 5 units to the left, subtract 5 from the \(x\) - coordinate of each point. So the new \(x\) - coordinates are \(A_x'=4 - 5=-1\), \(B_x'=7 - 5 = 2\), \(C_x'=9 - 5=4\), \(D_x'=4 - 5=-1\).

Step3: Apply down - translation rule

To move 2 units down, subtract 2 from the \(y\) - coordinate of each point. So the new \(y\) - coordinates are \(A_y'=-2-2=-4\), \(B_y'=-3 - 2=-5\), \(C_y'=0 - 2=-2\), \(D_y'=3 - 2 = 1\).
The new coordinates are \(A'(-1,-4)\), \(B'(2,-5)\), \(C'(4,-2)\), \(D'(-1,1)\).

Answer:

A'(-1,-4), D'(-1,1), C'(4,-2), B'(2,-5)