Question

travel a car leaves seattle traveling at a speed of 50 miles per hour. two hours later, a second car leaves seattle traveling at a speed of 60 miles per hour. the cars distances from seattle at time t hours are shown in the table. car a b distance (miles) 50t 60(t - 2) after how much time t will the two cars be the same distance from seattle? a) 10 hours b) the cars will never be the same distance from seattle c) 5 hours d) 12 hours

Explanation:

Step1: Set distances equal

$50t = 60(t-2)$

Step2: Expand right-hand side

$50t = 60t - 120$

Step3: Rearrange terms

$60t - 50t = 120$

Step4: Solve for t

$10t = 120 \implies t = \frac{120}{10} = 12$

Answer:

D) 12 hours