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in triangle abc, angle a is a right angle, cos(c) = 21/29, and the leng…

Question

in triangle abc, angle a is a right angle, cos(c) = 21/29, and the length of side bc is 58 units. what is the length, in units, of side ac? a 20 b 21 c 40 d 42

Explanation:

Step1: Recall cosine definition

In right - triangle \(ABC\) with right - angle at \(A\), \(\cos(C)=\frac{AC}{BC}\).

Step2: Substitute known values

We know that \(\cos(C)=\frac{21}{29}\) and \(BC = 58\) units. Let \(AC=x\). Then \(\frac{x}{58}=\frac{21}{29}\).

Step3: Solve for \(AC\)

Cross - multiply: \(29x=21\times58\). Then \(x = 21\times\frac{58}{29}=21\times2 = 42\).

Answer:

42