Question

1. triangle efg with side fe = 8 yd, side fg = 5 yd, side eg = 6 yd (the image shows triangle efg with vertices f, g, e; fg is 5 yd, eg is 6 yd, fe is 8 yd)

Explanation:

Assuming the problem is to find the area of triangle \( EFG \) (since it's a triangle with sides \( FG = 5 \) yd, \( EG = 6 \) yd, and \( EF = 8 \) yd, and \( \angle G \) is a right angle as it looks like a right triangle with \( FG \) and \( EG \) as legs):

Step1: Identify the base and height

The triangle is a right triangle with legs \( FG = 5 \) yd (base) and \( EG = 6 \) yd (height).

Step2: Use the area formula for a right triangle

The area \( A \) of a right triangle is given by \( A=\frac{1}{2}\times\text{base}\times\text{height} \). Substituting the values, we get \( A = \frac{1}{2}\times5\times6 \).

Step3: Calculate the area

\( \frac{1}{2}\times5\times6 = \frac{30}{2}=15 \).

Answer:

The area of triangle \( EFG \) is \( 15 \) square yards.