Question

triangle jkl is similar to triangle xyz. find k and m.

Explanation:

Answer:

Since the triangles are similar, the ratios of corresponding - sides are equal.
We have the proportion \(\frac{12}{10}=\frac{15}{m}=\frac{k}{13}\).
First, solve \(\frac{12}{10}=\frac{15}{m}\):
Cross - multiply: \(12m = 15\times10\), so \(12m=150\), and \(m=\frac{150}{12}=\frac{25}{2} = 12.5\).
Next, solve \(\frac{12}{10}=\frac{k}{13}\):
Cross - multiply: \(10k = 12\times13\), so \(10k = 156\), and \(k=\frac{156}{10}=15.6\)

So \(k = 15.6\) and \(m = 12.5\)