Question

if this triangle was reflected over the y-axis to form δh′j′k′, what would be the coordinates of vertex k′?
graph of a triangle on a coordinate grid with vertices h, j, k; x-axis and y-axis labeled, grid lines visible
note: enter your answer in the (x,y)
coordinates of vertex k′ are blank.

Explanation:

Step1: Determine original coordinates of K

From the graph, vertex \( K \) has coordinates \( (6, 6) \).

Step2: Apply reflection over y - axis rule

The rule for reflecting a point \( (x, y) \) over the \( y \)-axis is \( (x, y)\to(-x, y) \).
For point \( K(6, 6) \), applying the rule: \( x = 6 \) becomes \( - 6 \), \( y = 6 \) remains \( 6 \). So the coordinates of \( K' \) are \( (-6, 6) \).

Answer:

\((-6, 6)\)