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Question
- triangle xyz with vertices x(3, -2), y(6, 1), and z(5, -7): 180° image of a grid with a triangle drawn on it x(, ) y(, ) z(, )
Step1: Recall 180° rotation rule
For a point \((x, y)\), a 180° rotation about the origin gives \((-x, -y)\).
Step2: Rotate \(X(3, -2)\)
Apply the rule: \(x = 3\), \(y = -2\). So \(X' = (-3, 2)\).
Step3: Rotate \(Y(6, 1)\)
Apply the rule: \(x = 6\), \(y = 1\). So \(Y' = (-6, -1)\).
Step4: Rotate \(Z(5, -7)\)
Apply the rule: \(x = 5\), \(y = -7\). So \(Z' = (-5, 7)\).
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\(X'(-3, 2)\), \(Y'(-6, -1)\), \(Z'(-5, 7)\)