Question

troy pushes on a car for 2 seconds, during which he applies an impulse of 55 kg·m/s. what force does he apply to the car? a. 55 n b. 27.5 n c. 110 n d. 0.36 n

Explanation:

Step1: Recall impulse - force formula

The formula for impulse $J$ is $J = F\times\Delta t$, where $J$ is impulse, $F$ is force and $\Delta t$ is time interval.

Step2: Rearrange formula to solve for force

We can rewrite the formula as $F=\frac{J}{\Delta t}$.

Step3: Substitute given values

Given $J = 55\ kg\cdot m/s$ and $\Delta t=2\ s$. Then $F=\frac{55\ kg\cdot m/s}{2\ s}=27.5\ N$.

Answer:

B. 27.5 N