Question

two balls of different masses are rolled down a hill at different velocities. they data of these events are recorded below. ball 1trial 1 ball 1trial 2 ball 2 trial 1 ball 2 trial 2 mass (g) 50 50 100 100 velocity (m/s) 2 4 2 4 4. solve for the kinetic energy of ball 1 trial 1 using the formula below. (j) kinetic energy = mass x velocity² / 2 50 j 100 j 150 j 200 j

Explanation:

Step1: Identify mass and velocity for Ball 1 Trial 1

Mass $m = 50$ g, velocity $v=2$ m/s.

Step2: Convert mass to kg

Since $1$ kg = $1000$ g, $m = 50\div1000=0.05$ kg.

Step3: Apply kinetic - energy formula

The kinetic - energy formula is $KE=\frac{1}{2}mv^{2}$. Substitute $m = 0.05$ kg and $v = 2$ m/s into the formula: $KE=\frac{1}{2}\times0.05\times2^{2}$.

Step4: Calculate the result

First, calculate $2^{2}=4$. Then, $\frac{1}{2}\times0.05\times4 = 0.1$ J. But it seems there is a wrong formula in the problem description (it should be $KE=\frac{1}{2}mv^{2}$ instead of $KE = \frac{Mass\times Velocity^{2}}{2}$ in a wrong - written form). If we follow the wrong - written formula in the problem: $KE=\frac{50\times2^{2}}{2}=\frac{50\times4}{2}=100$ J.

Answer:

100 J