Question

two balls of different masses are rolled down a hill at different velocities. they data of these events are recorded below. mass (g): ball 1 trial 1 50, ball 1 trial 2 50, ball 2 trial 1 100, ball 2 trial 2 100. velocity (m/s): ball 1 trial 1 2, ball 1 trial 2 4, ball 2 trial 1 2, ball 2 trial 2 4. 1. did ball 1 or ball 2 have more kinetic energy in trial 1. * required 1

Explanation:

Step1: Recall kinetic - energy formula

The formula for kinetic energy is $KE=\frac{1}{2}mv^{2}$, where $m$ is the mass and $v$ is the velocity.

Step2: Calculate kinetic energy of Ball 1 in Trial 1

For Ball 1 in Trial 1, $m = 50g=0.05kg$ and $v = 2m/s$. Then $KE_1=\frac{1}{2}\times0.05\times2^{2}=\frac{1}{2}\times0.05\times4 = 0.1J$.

Step3: Calculate kinetic energy of Ball 2 in Trial 1

For Ball 2 in Trial 1, $m = 100g = 0.1kg$ and $v = 2m/s$. Then $KE_2=\frac{1}{2}\times0.1\times2^{2}=\frac{1}{2}\times0.1\times4=0.2J$.

Step4: Compare the kinetic energies

Since $0.2J>0.1J$, Ball 2 has more kinetic energy in Trial 1.

Answer:

Ball 2