Question

two parallel lines are crossed by a transversal. what is the value of k? (2k + 11)° 131° o k = 9 o k = 20 o k = 60 o k = 71

Explanation:

Step1: Identify angle - relationship

When two parallel lines are crossed by a transversal, corresponding angles are equal. The angle \((2k + 11)^{\circ}\) and \(131^{\circ}\) are corresponding angles. So, \(2k+11 = 131\).

Step2: Solve the equation for k

Subtract 11 from both sides of the equation: \(2k=131 - 11\). So, \(2k = 120\).

Step3: Find the value of k

Divide both sides of the equation \(2k = 120\) by 2. We get \(k=\frac{120}{2}=60\).

Answer:

k = 60