Question

type the correct answer in the box. use numerals instead of words. how many possible 3 - digit area codes exist if 0 cant be the first digit, but digits can repeat? a total of different 3 - digit area codes exist.

Explanation:

Step1: Count first digit options

First digit: 1-9, so 9 choices.

Step2: Count second digit options

Second digit: 0-9, so 10 choices.

Step3: Count third digit options

Third digit: 0-9, so 10 choices.

Step4: Calculate total combinations

Total = $9 \times 10 \times 10 = 900$

Answer:

900