QUESTION IMAGE
Question
type the correct answer in the box. use numerals instead of words. for this question, an answer that is not a whole number should be entered as a decimal, rounded to the thousandths place. management at a restaurant is deciding whether to add a new italian or chinese dish to their menu. they randomly select customers to survey whether or not they would order each type of cuisine. the survey responses are shown in the two - way frequency table. use the table to complete the statements. the probability that a customer would order italian is . the probability that a customer would order chinese and would not order italian is . the probability that a customer would order italian given that they would not order chinese is .
| would order chinese | would not order chinese | total | |
|---|---|---|---|
| would not order italian | 25 | 14 | 39 |
| total | 68 | 34 | 102 |
Step1: Recall conditional - probability formula
The formula for conditional probability is $P(A|B)=\frac{P(A\cap B)}{P(B)}$. In terms of frequencies from a two - way table, if we want to find the probability that a customer would order Italian given that they would not order Chinese, we use the formula $P(\text{Italian}|\text{Not Chinese})=\frac{n(\text{Italian}\cap\text{Not Chinese})}{n(\text{Not Chinese})}$.
Step2: Identify relevant values from the table
The number of customers who would not order Chinese is $n(\text{Not Chinese}) = 34$. The number of customers who would not order Chinese and would order Italian is $n(\text{Italian}\cap\text{Not Chinese})=25$.
Step3: Calculate the probability
$P(\text{Italian}|\text{Not Chinese})=\frac{25}{34}\approx0.735$
The probability that a customer would order Chinese and would not order Italian is found in a similar way. The number of customers who would not order Italian is $n(\text{Not Italian}) = 68$. The number of customers who would order Chinese and would not order Italian is $n(\text{Chinese}\cap\text{Not Italian}) = 43$. So the probability $P(\text{Chinese}|\text{Not Italian})=\frac{43}{68}\approx0.632$
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0.735
0.632