Question

type the correct answer in each box. use numerals instead of words. consider the equation below. \\(\frac{x}{h} + 1 = -2\\) the value of x in terms of h is \\(\square\\). the value of x when h = 4 is \\(\square\\).

Explanation:

Step1: Solve for \( x \) in terms of \( h \)

We start with the equation \( \frac{x}{h} + 1 = -2 \). First, subtract 1 from both sides of the equation to isolate the term with \( x \).
\[
\frac{x}{h} + 1 - 1 = -2 - 1
\]
Simplifying both sides, we get:
\[
\frac{x}{h} = -3
\]
Next, multiply both sides by \( h \) to solve for \( x \):
\[
x = -3h
\]

Step2: Find \( x \) when \( h = 4 \)

Substitute \( h = 4 \) into the expression we found for \( x \) (which is \( x = -3h \)):
\[
x = -3 \times 4
\]
Simplifying the right side:
\[
x = -12
\]

Answer:

The value of \( x \) in terms of \( h \) is \(-3h\).
The value of \( x \) when \( h = 4 \) is \(-12\).