Question

type the correct answer in each box. use numerals instead of words. consider function h. \\( h(x) = \

$$\begin{cases} 3x - 4, & x < 0 \\\\ 2x^2 - 3x + 10, & 0 \\leq x < 4 \\\\ 2^x, & x \\geq 4 \\end{cases}$$

\\) what are the values of the function when \\( x = 0 \\) and when \\( x = 4 \\)? \\( h(0) = \square \\) \\( h(4) = \square \\)

Explanation:

Step1: Select formula for $x=0$

Use $h(x)=2x^2-3x+10$ (since $0\leq x<4$)

Step2: Calculate $h(0)$

Substitute $x=0$:
$h(0)=2(0)^2 - 3(0) + 10 = 0 - 0 + 10 = 10$

Step3: Select formula for $x=4$

Use $h(x)=2^x$ (since $x\geq4$)

Step4: Calculate $h(4)$

Substitute $x=4$:
$h(4)=2^4 = 16$

Answer:

$h(0) = 10$
$h(4) = 16$