Question

type of electromagnetic radiation frequency range (hz) energy range (j) ultraviolet 7.5×10^14 - 3×10^16 5×10^(-19) - 2×10^(-17) visible? ? infrared 3×10^11 - 4×10^14 2×10^(-22) - 3×10^(-19) the frequency and energy ranges of photons in some parts of the electromagnetic spectrum are given in the table above. which of the following could be the energy of a photon in the visible range? a 9×10^(-21) j b 4×10^(-20) j c 4×10^(-19) j d 9×10^(-19) j

Explanation:

Step1: Identify energy - range relationship

The energy of electromagnetic radiation increases with frequency. Visible light has a frequency range between infrared and ultraviolet. So, its energy range should be between the energy range of infrared and ultraviolet.

Step2: Determine the energy range limits

The energy range of infrared is $2\times 10^{-22}-3\times 10^{-19}\text{ J}$ and the energy range of ultraviolet is $5\times 10^{-19}-2\times 10^{-17}\text{ J}$. So, the energy of visible - light photons should be in the range $3\times 10^{-19}\text{ J}

Answer:

C. $4\times 10^{-19}\text{ J}$