Question

type the missing digits:
9 4 8

• □ 5 □

-------
2 □ 0
submit

Explanation:

Step1: Analyze the units place

In the units place, we have \(8 - \text{digit} = 0\). So, the digit in the units place of the subtrahend must be \(8\) because \(8 - 8 = 0\). So the subtrahend's units digit is \(8\).

Step2: Analyze the tens place

Now, looking at the tens place: we have \(4 - 5\). But \(4\) is less than \(5\), so we need to borrow from the hundreds place. After borrowing, the \(4\) becomes \(14\), and we subtract \(5\) from \(14\). So \(14 - 5=\text{digit in the tens place of the difference}\). Let's calculate that: \(14 - 5 = 9\). So the tens digit of the difference is \(9\).

Step3: Analyze the hundreds place

After borrowing \(1\) from the hundreds place of the minuend (which was \(9\)), it becomes \(8\). Now, we have \(8 - \text{digit (hundreds place of subtrahend)} = 2\). So, the digit in the hundreds place of the subtrahend is \(8 - 2 = 6\)? Wait, no, wait. Wait, the minuend's hundreds digit was \(9\), we borrowed \(1\) for the tens place, so it becomes \(8\). Then \(8 - \text{subtrahend's hundreds digit} = 2\). So \(\text{subtrahend's hundreds digit}=8 - 2 = 6\)? Wait, no, wait, let's re - check. Wait, the minuend is \(948\), subtrahend is \(\square5\square\), difference is \(2\square0\).

Wait, hundreds place: \(9 - 1\) (because we borrowed for tens place) \(-\text{subtrahend's hundreds digit}=2\). So \(8 - \text{subtrahend's hundreds digit}=2\), so \(\text{subtrahend's hundreds digit}=8 - 2 = 6\)? Wait, no, wait, let's do it again.

Minuend: \(9\) (hundreds), \(4\) (tens), \(8\) (units)

Subtrahend: \(a\) (hundreds), \(5\) (tens), \(8\) (units) (we found units digit is \(8\))

Difference: \(2\) (hundreds), \(b\) (tens), \(0\) (units)

Tens place: \(4 - 5\), can't do, so borrow from hundreds. So \(9\) becomes \(8\), \(4\) becomes \(14\). Then \(14 - 5 = b\), so \(b = 9\).

Hundreds place: \(8 - a=2\), so \(a = 8 - 2=6\).

So putting it all together:

Subtrahend: \(658\)

Difference: \(290\)

Let's verify: \(948-658 = 290\). Let's check: \(948-600 = 348\), \(348 - 58=290\). Yes, that works.

Answer:

The subtrahend is \(658\) and the difference is \(290\). So the missing digits are: subtrahend's hundreds digit \(6\), units digit \(8\), and difference's tens digit \(9\). So the filled - in problem is:

\[

$$\begin{array}{r} 948\\ - 658\\ \hline 290 \end{array}$$

\]

So the missing digits are (from left to right in the subtrahend and then the difference): \(6\) (hundreds place of subtrahend), \(8\) (units place of subtrahend), \(9\) (tens place of difference).