Question

tyrone $1\frac{1}{4}$
farid $1\frac{1}{8}$
darnel $1\frac{7}{8}$
josh $1\frac{1}{4}$
zoe $1$
abdul $1\frac{3}{4}$
use the data in the table to complete the line plot below.
click to select the xs. to clear a column, click on the number line below it.
age difference
number line with marks 1, $1\frac{1}{8}$, $1\frac{1}{4}$, $1\frac{3}{8}$, $1\frac{1}{2}$, $1\frac{5}{8}$, $1\frac{3}{4}$, $1\frac{7}{8}$ and xs

Explanation:

Step1: Analyze each data point

• Zoe: \(1\) → mark an X at \(1\) (already has one green X, need to check count. Wait, original data: Zoe has \(1\), so count for \(1\) is 1 (but in the plot, maybe we need to count all. Wait, let's list all data:

Tyrone: \(1\frac{1}{4}\), Farid: \(1\frac{1}{8}\), Darnel: \(1\frac{7}{8}\), Josh: \(1\frac{1}{4}\), Zoe: \(1\), Abdul: \(1\frac{3}{4}\)

Step2: Count occurrences for each value

• \(1\): Zoe → 1 occurrence (plot has one green X, maybe correct)
• \(1\frac{1}{8}\): Farid → 1 occurrence (plot has one green X at \(1\frac{1}{8}\), correct)
• \(1\frac{1}{4}\): Tyrone, Josh → 2 occurrences (plot has two green Xs at \(1\frac{1}{4}\), correct)
• \(1\frac{3}{4}\): Abdul → 1 occurrence (need to mark an X at \(1\frac{3}{4}\))
• \(1\frac{7}{8}\): Darnel → 1 occurrence (need to mark an X at \(1\frac{7}{8}\))
• \(1\frac{3}{8}\): None → 0
• \(1\frac{1}{2}\): None → 0
• \(1\frac{5}{8}\): None → 0

Step3: Mark missing Xs

• At \(1\frac{3}{4}\): add one X
• At \(1\frac{7}{8}\): add one X

Answer:

• For \(1\frac{3}{4}\): mark an X (click on the column above \(1\frac{3}{4}\))
• For \(1\frac{7}{8}\): mark an X (click on the column above \(1\frac{7}{8}\))