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- under her cell phone plan, yaritza pays a flat co\\$65 per month and \\$4 per gigabyte. she wants to keep hebill under \\$95 per month. which inequality can be used todetermine ( x ), the maximum number of gigabytes yaritzacan use while staying within her budget?a. ( 65 + 4x > 95 )b. ( 4 + 65x < 95 )c. ( 4 + 65x > 95 )d. ( 65 + 4x < 95 )9. members of a softball team raised \\$1350.75 to go to atournament. they rented a bus for \\$873.50 and budgeted\\$20.75 per player for meals. determine the number ofplayers the team can bring to the tournament.10. yasmin needs to order some new supplies for therestaurant where she works. the restaurant needs at least393 spoons. there are currently 241 spoons. if each set onsale contains 8 spoons, write an inequality representing ( s ),the number of sets of spoons yasmin should buy.
Question 8
Step1: Analyze the cost components
The flat cost is $65, and the cost per gigabyte is $4. Let \( x \) be the number of gigabytes. So the total cost is the flat cost plus the cost for \( x \) gigabytes, which is \( 65 + 4x \).
Step2: Set up the inequality
She wants her bill under $95, meaning the total cost \( 65 + 4x \) is less than 95. So the inequality is \( 65 + 4x < 95 \).
Step1: Find the remaining money for meals
The total money raised is $1350.75, and the bus rental costs $873.50. So the money left for meals is \( 1350.75 - 873.50 \).
\[ 1350.75 - 873.50 = 477.25 \]
Step2: Calculate the number of players
Each player's meal budget is $20.75. Let \( n \) be the number of players. The total meal cost is \( 20.75n \), which should be less than or equal to the remaining money. So we solve \( 20.75n \leq 477.25 \) for \( n \).
\[ n=\frac{477.25}{20.75}=23 \]
Step1: Analyze the spoon quantity
Currently, there are 241 spoons. Each set has 8 spoons, and she buys \( s \) sets. So the total number of spoons after buying \( s \) sets is \( 241 + 8s \).
Step2: Set up the inequality
The restaurant needs at least 393 spoons, so \( 241 + 8s \geq 393 \).
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D. \( 65 + 4x < 95 \)