QUESTION IMAGE
Question
6 from unit 2, lesson 17
elena writes the equation 6x + 2y = 12. write a new equation that has:
a. exactly one solution in common with elena’s equation
b. no solutions in common with elena’s equation
c. infinitely many solutions in common with elena’s equation
7 from unit 3, lesson 9
a restaurant owner wants to see if there is a relationship between the amount of sugar in some food items on her menu and how popular the items are.
she creates a scatter plot to show the relationship between amount of sugar in menu items and the number of orders for those items. the correlation coefficient for the line of best fit is 0.58.
a. are the two variables correlated?
explain your reasoning.
b. is it likely or unlikely that one of the variables causes the other to change?
explain your reasoning.
Problem 6
Part a
Step1: Recall solution conditions
For a system of linear equations \(a_1x + b_1y = c_1\) and \(a_2x + b_2y = c_2\), exactly one solution occurs when \(\frac{a_1}{a_2}
eq\frac{b_1}{b_2}\). Elena's equation is \(6x + 2y = 12\). Let's choose a new equation, say \(x + y = 1\) (here \(a_1 = 6, b_1 = 2\); \(a_2 = 1, b_2 = 1\), and \(\frac{6}{1}
eq\frac{2}{1}\)).
Step2: Verify
The system \(
\) can be solved. From the second equation, \(y = 1 - x\). Substitute into the first: \(6x + 2(1 - x)=12\Rightarrow6x + 2 - 2x = 12\Rightarrow4x = 10\Rightarrow x=\frac{5}{2}\), \(y = 1-\frac{5}{2}=-\frac{3}{2}\), so only one solution.
Step1: Recall no - solution condition
For a system of linear equations \(a_1x + b_1y = c_1\) and \(a_2x + b_2y = c_2\), no solutions occur when \(\frac{a_1}{a_2}=\frac{b_1}{b_2}
eq\frac{c_1}{c_2}\). Elena's equation is \(6x + 2y = 12\). Let's take \(6x + 2y = 1\). Here \(\frac{6}{6}=\frac{2}{2}=1\), but \(\frac{12}{1}=12
eq1\).
Step2: Verify
The system \(
\) has the same left - hand side but different right - hand sides, so no solutions.
Step1: Recall infinite - solutions condition
For a system of linear equations \(a_1x + b_1y = c_1\) and \(a_2x + b_2y = c_2\), infinite solutions occur when \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\). Elena's equation is \(6x + 2y = 12\). Let's multiply Elena's equation by \(\frac{1}{2}\), we get \(3x + y = 6\). Here \(\frac{6}{3}=\frac{2}{1}=\frac{12}{6}=2\).
Step2: Verify
The equation \(3x + y = 6\) can be rewritten as \(6x + 2y = 12\) (multiply both sides by 2), so every solution of Elena's equation is a solution of \(3x + y = 6\) and vice - versa.
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\(x + y = 1\) (any equation with \(\frac{6}{a_2}
eq\frac{2}{b_2}\) works)