Question

unit test:
one - variable linear equations and inequal
solve for x.
$5 + \frac{4}{7}(21 + 3x) = 41$
enter your answer in the box.
$x = \square$

Explanation:

Step1: Subtract 5 from both sides

$5 + \frac{4}{7}(21 + 3x) - 5 = 41 - 5$
$\frac{4}{7}(21 + 3x) = 36$

Step2: Multiply both sides by 7/4

$\frac{7}{4} \times \frac{4}{7}(21 + 3x) = 36 \times \frac{7}{4}$
$21 + 3x = 63$

Step3: Subtract 21 from both sides

$21 + 3x - 21 = 63 - 21$
$3x = 42$

Step4: Divide both sides by 3

$\frac{3x}{3} = \frac{42}{3}$
$x = 14$

Answer:

14