Question

use the data in the following table, which lists drive - thru order accuracy at popular fast food chains. assume that orders are randomly selected from those included in the table.
drive - thru restaurant

	a	b	c	d
order not accurate	34	60	33	13

if one order is selected, find the probability of getting an order from restaurant a or an order that is accurate. are the events of selecting an order from restaurant a and selecting an accurate order disjoint events?
the probability of getting an order from restaurant a or an order that is accurate is 0.907 (round to three decimal places as needed.)
are the events of selecting an order from restaurant a and selecting an accurate order disjoint events?
the events disjoint because it possible to

Explanation:

Step1: Calculate total number of orders

$331 + 280+243 + 142+34 + 60+33 + 13=1136$

Step2: Calculate number of orders from Restaurant A

$331 + 34=365$

Step3: Calculate number of accurate orders

$331+280 + 243+142 = 996$

Step4: Calculate number of accurate orders from Restaurant A

$331$

Step5: Use the addition - rule for probability

$P(A\ or\ accurate)=P(A)+P(accurate)-P(A\ and\ accurate)$
$P(A)=\frac{365}{1136}$, $P(accurate)=\frac{996}{1136}$, $P(A\ and\ accurate)=\frac{331}{1136}$
$P(A\ or\ accurate)=\frac{365 + 996-331}{1136}=\frac{1030}{1136}\approx0.907$

Step6: Determine if events are disjoint

Disjoint events cannot occur at the same time. Since there are accurate orders from Restaurant A (331 of them), it is possible to select an order that is from Restaurant A and is accurate. So the events are not disjoint.

Answer:

The probability of getting an order from Restaurant A or an order that is accurate is approximately $0.907$. The events are not disjoint because it is possible to select an order from Restaurant A that is accurate.