Question

use the diagram to complete the statement. given △jkl, sin(38°) equals cos(38°). tan(38°). tan(52°). cos(52°).

Explanation:

Step1: Recall trigonometric co - function identity

In a right - triangle, $\sin\theta=\cos(90^{\circ}-\theta)$.

Step2: Calculate the complementary angle

Given $\theta = 38^{\circ}$, then $90^{\circ}-\theta=90^{\circ}-38^{\circ}=52^{\circ}$. So, $\sin(38^{\circ})=\cos(52^{\circ})$.

Answer:

$\cos(52^{\circ})$