Question

use the distributive property to expand the expression.
\frac{1}{3}(-15x + 9) = \frac{1}{3}(\square x) + \frac{1}{3}(? )

Explanation:

Step1: Apply distributive property

The distributive property states $a(b+c)=ab+ac$. Here, $a=\frac{1}{3}$, $b=-15x$, $c=9$.

Step2: Split the terms

$\frac{1}{3}(-15x + 9) = \frac{1}{3}(-15x) + \frac{1}{3}(9)$

Answer:

$\frac{1}{3}(-15x) + \frac{1}{3}(9)$