Question

use the function $f(x) = 2x^3 - 3x^2 + 7$ to complete the exercises.
$f(-1) = square$
$f(1) = square$
$f(2) = square$

Explanation:

Step1: Substitute $x=-1$ into $f(x)$

$f(-1)=2(-1)^3 - 3(-1)^2 + 7$

Step2: Calculate powers and simplify

$f(-1)=2(-1) - 3(1) + 7 = -2 - 3 + 7 = 2$

Step3: Substitute $x=1$ into $f(x)$

$f(1)=2(1)^3 - 3(1)^2 + 7$

Step4: Calculate powers and simplify

$f(1)=2(1) - 3(1) + 7 = 2 - 3 + 7 = 6$

Step5: Substitute $x=2$ into $f(x)$

$f(2)=2(2)^3 - 3(2)^2 + 7$

Step6: Calculate powers and simplify

$f(2)=2(8) - 3(4) + 7 = 16 - 12 + 7 = 11$

Answer:

$f(-1)=2$
$f(1)=6$
$f(2)=11$