Question

use the graph to complete each statement about this situation.
the maximum profit the florist will earn from selling celebration bouquets is $
the florist will break - even after one - dollar decreases.
the interval of the number of one - dollar decreases for which the florist makes a profit from celebration bouquets is ( , ).

Explanation:

Step1: Identify max profit (vertex)

The highest point (vertex) of the parabola is at $y=600$.

Step2: Find break-even points (x-intercepts)

The parabola crosses the x-axis at $x=-10$ and $x=20$. Since we consider positive one-dollar decreases, the relevant intercept is $x=20$, and the other intercept $x=-10$ represents 10 one-dollar increases, but the break-even for decreases is 20.

Step3: Determine profit interval

Profit occurs where $y>0$, between the x-intercepts. Translating to valid one-dollar decreases, the interval is from 0 (no decrease) to 20, since negative x-values are increases, not decreases.

Answer:

The maximum profit the florist will earn from selling celebration bouquets is $\boldsymbol{600}$
The florist will break-even after $\boldsymbol{20}$ one-dollar decreases.
The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is $\boldsymbol{(0, 20)}$