Question

use the product rule to simplify the expression. write the result using exponents.
$(-3b^2c^6)(3bc^2)$
$(-3b^2c^6)(3bc^2)=\square$

Explanation:

Step1: Multiply the coefficients

$(-3) \times 3 = -9$

Step2: Combine $b$ terms (product rule)

$b^2 \times b^1 = b^{2+1} = b^3$

Step3: Combine $c$ terms (product rule)

$c^6 \times c^2 = c^{6+2} = c^8$

Step4: Combine all results

Multiply the coefficient result with the variable results.

Answer:

$-9b^3c^8$