Question

use software or a calculator to find the range, variance, and standard deviation of the following body temperatures, in degrees fahrenheit, taken at 12:00 a.m. click the icon to view the table of body temperatures. the range of the data set is 3.40°f (round to two decimal places as needed.) the standard deviation, s, of the data set is 0.69°f (round to two decimal places as needed.) the variance, s², of the data set is (°f)² (round to two decimal places as needed.) data table 98.6 98.5 97.7 97.9 98.6 98.2 98.6 98.9 98.2 98.2 98.5 98.6 98.6 97.4 96.6 99.3 97.5 97.9 98.7 98.1 98.3 98.3 98.2 97.4 98.5 97.7 98.5 98.7 99.7 97.6 97.4 97.6 98.5 99.5 99 99.9 98.5 97.8 98.8 98.7 96.7 98.6 98.7 98.6 98.2 97.9 98 98.3 98.9 98.7 98.3 99.2 96.5 97.7 97.7 97.4 97.3 97.2 97.5 98.3 96.9 97.6 97.3 97.8 98.2 98.9 98.8 98.2 97.4 97.6 96.7 97 99 98.7 98.7 98 98.9 98.4 98.7 98.9 98.6 99.3 98.9 97.5 98.9 98.4 98.2 98.2 98.6 98.7 98.8 98.8 97.6 98.6 98.6 98.1 98.1 99.6 97.7 98.3 98 97.8 98.2 97.5 97.9 97.4

Explanation:

Step1: Recall variance - standard deviation relationship

The variance $s^{2}$ is the square of the standard deviation $s$.

Step2: Calculate variance

Given $s = 0.69$, then $s^{2}=0.69^{2}=0.4761$. Rounding to two decimal places, $s^{2}\approx0.48$.

Answer:

$0.48$