Question

1. use a standard inch ruler to answer each question. then, write a multipl equation and a division equation that answer the question.

a. how many \\(\frac{1}{2}\\)s are in 8?

b. how many \\(\frac{3}{16}\\)s are in \\(2\frac{1}{4}\\)?

c. how many \\(\frac{5}{8}\\)s are in 10?

Explanation:

Step1: Solve part a: Count 1/2s in 8

To find how many $\frac{1}{2}$ are in 8, divide 8 by $\frac{1}{2}$, which is equivalent to multiplying by its reciprocal.
Multiplication equation: $8 \times 2 = 16$
Division equation: $8 \div \frac{1}{2} = 16$

Step2: Solve part b: Count 3/16s in 2 1/4

First, convert the mixed number to an improper fraction: $2\frac{1}{4} = \frac{9}{4}$. Then divide by $\frac{3}{16}$ (multiply by reciprocal $\frac{16}{3}$).
Multiplication equation: $\frac{9}{4} \times \frac{16}{3} = 12$
Division equation: $\frac{9}{4} \div \frac{3}{16} = 12$

Step3: Solve part c: Count 5/8s in 10

Divide 10 by $\frac{5}{8}$, which is multiplying by reciprocal $\frac{8}{5}$.
Multiplication equation: $10 \times \frac{8}{5} = 16$
Division equation: $10 \div \frac{5}{8} = 16$

Answer:

a. Number of $\frac{1}{2}$s: 16
Multiplication equation: $8 \times 2 = 16$
Division equation: $8 \div \frac{1}{2} = 16$

b. Number of $\frac{3}{16}$s: 12
Multiplication equation: $\frac{9}{4} \times \frac{16}{3} = 12$
Division equation: $\frac{9}{4} \div \frac{3}{16} = 12$

c. Number of $\frac{5}{8}$s: 16
Multiplication equation: $10 \times \frac{8}{5} = 16$
Division equation: $10 \div \frac{5}{8} = 16$