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7. using 120 for the wall length, assume there are 6 corners, 5 interse…

Question

  1. using 120 for the wall length, assume there are 6 corners, 5 intersections, 10 openings, and the framing is 24\ oc. find the number of studs needed, including outside walls and partitions.

Explanation:

Step1: Convert wall length to inches

Since 1 foot = 12 inches, a 120 - foot wall length is $120\times12=1440$ inches.

Step2: Calculate number of studs for length

The framing is 24 inches on - center (OC). The number of studs for the length is $\frac{1440}{24}+1 = 61$ (we add 1 because we need a stud at the start).

Step3: Account for corners

Each corner requires an additional stud. With 6 corners, we add 6 studs.

Step4: Account for intersections

Each intersection requires an additional stud. With 5 intersections, we add 5 studs.

Step5: Account for openings

Each opening usually requires 2 additional studs. With 10 openings, we add $10\times2 = 20$ studs.

Step6: Calculate total number of studs

The total number of studs is $61+6 + 5+20=92$.

Answer:

92