Question

using desmos, write the equation for the following data points. round to the nearest tenth.

x	y
-2	6
6	-4

$y = 0.96x + 0.93$
$y = 1.12x + -1.02$
$y = 0.83x + -0.8$
$a^{2}+b^{2}=c^{2}$

Explanation:

Step1: Identify data points

The data points are $(-2, -1)$ and $(6, -4)$.

Step2: Calculate slope $m$

Slope formula: $m=\frac{y_2-y_1}{x_2-x_1}$
$m=\frac{-4 - (-1)}{6 - (-2)}=\frac{-3}{8}=-0.375$

Step3: Find y-intercept $b$

Use point $(-2, -1)$ in $y=mx+b$:
$-1 = -0.375(-2)+b$
$-1 = 0.75 + b$
$b = -1 - 0.75 = -1.75$

Step4: Round to nearest tenth

Slope: $-0.375 \approx -0.4$, intercept: $-1.75 \approx -1.8$
Equation: $y=-0.4x-1.8$
(Note: Rechecking, if using linear regression properly for the two points, the exact equation is $y=-\frac{3}{8}x-\frac{7}{4}$, which rounds to $y=-0.4x-1.8$. None of the given linear equations match, but the correct regression equation is derived as above.)

Answer:

$y=-0.4x-1.8$