Question

using the quotient of powers rule we know that
\frac{x^2}{x^2} = x^{2 - 2} = x^0.

we also know that \frac{x^2}{x^2} = 1 since any number divided by itself is 1.

assuming that x≠0, use the argument shown to determine the value of x^0.

a. \bigcirc 1

b. \bigcirc undefined

c. \bigcirc \frac{1}{2}

d. \bigcirc 0

e. \bigcirc 2

Explanation:

Step1: Equate the two expressions

We have two expressions for $\frac{x^2}{x^2}$: $\frac{x^2}{x^2}=x^{2-2}=x^0$ and $\frac{x^2}{x^2}=1$ (for $x
eq0$). So, $x^0 = 1$.

Answer:

A. 1