Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

in the venn diagram, ( x ) means: a {c, d, e, f, g, h} b {b, c, f, e} c…

Question

in the venn diagram, ( x ) means: a {c, d, e, f, g, h} b {b, c, f, e} c {a, b, c, d, e, f, g, h} d {a, d, g, h}

Explanation:

Brief Explanations

The complement of a set \( X \) (denoted as \( X' \)) in a universal set \( U \) includes all elements in \( U \) that are not in \( X \). In the Venn diagram, set \( X \) contains elements \( b, c, e, f \). The universal set \( U \) includes all elements \( a, b, c, d, e, f, g, h \). So, \( X' \) will be the elements in \( U \) but not in \( X \), which are \( a, d, g, h \)? Wait, no, wait. Wait, let's re - examine. Wait, the set \( X \) is the circle labeled \( X \), so its elements are \( b \) (only in \( X \)), \( c \) (in \( X \cap Y \)), \( e \) (in \( X \cap Z \)), \( f \) (in \( X \cap Y \cap Z \)). So the universal set \( U \) has all regions: \( a \) (only in \( Y \)), \( b \) (only in \( X \)), \( c \) ( \( X \cap Y \) ), \( d \) (only in \( Y \)), \( e \) ( \( X \cap Z \) ), \( f \) ( \( X \cap Y \cap Z \) ), \( g \) ( \( Y \cap Z \) ), \( h \) (only in \( Z \) ). So \( X' \) is all elements not in \( X \). So elements not in \( X \) are \( a \) (not in \( X \)), \( d \) (not in \( X \)), \( g \) (not in \( X \)), \( h \) (not in \( X \))? Wait, no, that's option D? Wait, no, wait, maybe I made a mistake. Wait, let's list the elements of \( X \): \( X \) consists of the regions inside the \( X \) circle. So the \( X \) circle has \( b \) (only \( X \)), \( c \) ( \( X \cap Y \) ), \( e \) ( \( X \cap Z \) ), \( f \) ( \( X \cap Y \cap Z \) ). So the elements not in \( X \) are the elements in \( U \) but outside \( X \). So \( U \) has \( a, b, c, d, e, f, g, h \). Removing \( b, c, e, f \) (elements of \( X \)), we get \( a, d, g, h \). Wait, but option D is \( \{a, d, g, h\} \). Wait, but let's check the options again. Option A: \( \{c, d, e, f, g, h\} \) – no, because \( c \) and \( e \) and \( f \) are in \( X \). Option B: \( \{b, c, f, e\} \) – that's \( X \) itself. Option C: \( \{a, b, c, d, e, f, g, h\} \) – that's \( U \). Option D: \( \{a, d, g, h\} \) – these are elements not in \( X \). So the correct answer is D? Wait, no, wait, maybe I messed up the regions. Wait, the \( Y \) circle: \( a \) (outside \( X \) and \( Z \), inside \( Y \)), \( d \) (only \( Y \)), \( c \) ( \( X \cap Y \) ), \( f \) ( \( X \cap Y \cap Z \) ), \( g \) ( \( Y \cap Z \) ). The \( Z \) circle: \( h \) (only \( Z \)), \( e \) ( \( X \cap Z \) ), \( f \) ( \( X \cap Y \cap Z \) ), \( g \) ( \( Y \cap Z \) ). The \( X \) circle: \( b \) (only \( X \)), \( c \) ( \( X \cap Y \) ), \( e \) ( \( X \cap Z \) ), \( f \) ( \( X \cap Y \cap Z \) ). So the universal set \( U \) is the rectangle, so all elements \( a, b, c, d, e, f, g, h \). The complement of \( X \), \( X' \), is all elements in \( U \) not in \( X \). So elements not in \( X \) are \( a \) (in \( Y \), not \( X \)), \( d \) (in \( Y \), not \( X \)), \( g \) (in \( Y \cap Z \), not \( X \)), \( h \) (in \( Z \), not \( X \)). So \( X'=\{a, d, g, h\} \), which is option D. Wait, but earlier I thought maybe I was wrong, but now it seems correct. Wait, but let's check the options again. Option D is \( \{a, d, g, h\} \), so that's the complement of \( X \).

Answer:

D. \(\{a, d, g, h\}\)