Question

version a
test 2 (ch 5, 6, 8, 9)
february 28, 2023 p. 6/6

1. the end of a chromosome is the ____ while the attachment point to the spindle is the

a. centromere; telomere
b. telomere; centromere
c. centromere; locus
d. kinetochore; locus
e. telomere; kinetochore

1. which molecules are able to diffuse across a membrane without help or the expenditure of atp?

a. water, oxygen, carbon dioxide
b. water, ions, free radicals
c. oxygen, carbon dioxide, ions
d. ions, covalent, hydrogen
e. ions, large particles, substances against their gradient

1. some of the requirements for \prep\ are __. these reactions result in the production of __

a. nad⁺, co - enzyme a; nadh, co₂
b. adp, nad⁺; atp, nadh
c. nad⁺, fad, oxygen; nadh, fadh₂, atp
d. nad⁺, fad, adp; nadh, fadh₂, atp
e. atp, nadph; adp, nadp⁺

1. what is shown in the image at right?

a. a branching metabolic pathway, showing the importance of gene activation
b. competitive inhibition in metastasis
c. feedback inhibition
d. the importance of ingesting essential amino acids

1. how many nadh are made in the complete breakdown of glucose?

a. 1
b. 2
c. 3
d. 6
e. 10

1. consider the metabolic pathway shown here. to increase the build - up of intermediate f:

a. lots of enzyme 6, little enzyme 5
b. lots of enzyme 3, little enzyme 4
c. lots of enzyme 4, little enzyme 3
d. lots of enzyme 3, little enzyme 5
e. lots of enzyme 5, little enzyme 3
f. lots of enzyme 5, little enzyme 6
happy spring break!

Explanation:

1. The end of a chromosome is the telomere and the attachment point to the spindle is the kinetochore.
2. Small non - polar molecules like water, oxygen, and carbon dioxide can diffuse across a membrane without energy or help.
3. The prep reactions require NAD⁺ and Co - enzyme A and produce NADH and CO₂.
4. The image shows feedback inhibition where the end - product inhibits an earlier enzyme in the pathway.
5. In the complete breakdown of glucose, 10 NADH are produced (2 in glycolysis, 2 in the transition reaction, and 6 in the citric acid cycle).
6. To increase the build - up of intermediate F, we need lots of enzyme 5 (which converts C to F) and little enzyme 6 (which converts F to G).

Answer:

1. E. Telomere; kinetochore
2. A. Water, oxygen, carbon dioxide
3. A. NAD⁺, CoEnzyme A; NADH, CO₂
4. C. Feedback inhibition
5. E. 10
6. E. Lots of enzyme 5, little enzyme 6