Question

vincent weighed 6 blocks of unknown materials for a science experiment. the blocks weighed: 6 ounces 5 ounces 7 ounces 6 ounces 6 ounces 3 ounces what was the mean absolute deviation of the weights of the blocks? if the answer is a decimal, round it to the nearest tenth. mean absolute deviation (mad): ounces

Explanation:

Step1: Calculate the mean

First, find the sum of the weights: $6 + 5+7 + 6+6 + 3=33$ ounces. There are $n = 6$ blocks. The mean $\bar{x}=\frac{33}{6}=5.5$ ounces.

Step2: Calculate the absolute - deviations

For $x_1 = 6$, $\vert6 - 5.5\vert=0.5$; for $x_2 = 5$, $\vert5 - 5.5\vert = 0.5$; for $x_3 = 7$, $\vert7 - 5.5\vert=1.5$; for $x_4 = 6$, $\vert6 - 5.5\vert=0.5$; for $x_5 = 6$, $\vert6 - 5.5\vert=0.5$; for $x_6 = 3$, $\vert3 - 5.5\vert = 2.5$.

Step3: Calculate the mean of the absolute - deviations

The sum of the absolute - deviations is $0.5+0.5 + 1.5+0.5+0.5+2.5 = 6$. The mean absolute deviation (MAD) is $\frac{6}{6}=1$ ounce.

Answer:

1