Question

virtual density lab
plain water has a density of 1.0 g/ml. follow the directions carefully.

1. take the red box out of the cylinder and place it on the balance.
2. click on \turn the fluid into water.\
3. click on the object you are finding the density.
4. make a hypothesis (will the object sink (s) or float (f)) and write it in box 2.
5. drop the object into the cylinder. record the results (sink or float).
6. take the object out of the cylinder and place it on the balance and record the mass in grams.
7. drop it into the cylinder, subtract the new volume from the volume of the water (25.5 ml). dont forget the label of ml. ***if you dont complete this step correctly, your density will be incorrect.
8. solve for density (mass/volume). dont forget to record the label as g/ml.

object	hypothesis (sink or float)	results (sink or float)	mass (g)	volume (ml)	density (g/ml) (mass/volume)
iron	s	s	31.48	4	7.89
load	s	s	72.38	6.2	12.0
wood	f	f	1.95	27.5	0.071
foam	s	f	2.76	28.3	0.097
rubber	s	s	0.52	25.9	0.020
ice	f	f	9.2	34.7	0.265
mystery	s	s	18.58	31.2	0.596

calculations (make sure you add the formulas, substitutions, and labels,

density	mass 60g	volume 3cm³

density	mass 72g	volume 8cm³

density 7 g/cm³	mass	volume 9cm³

density 11 g/cm³	mass	volume 6cm³

density 3 g/cm³	mass 21g	volume

density 20 g/cm³	mass 400g	volume

Explanation:

First Calculation (Mass = 60g, Volume = 3cm³)

Step1: Recall density formula

The formula for density ($
ho$) is $
ho = \frac{\text{mass (}m\text{)}}{\text{volume (}V\text{)}}$.

Step2: Substitute values

Substitute $m = 60\ \text{g}$ and $V = 3\ \text{cm}^3$ into the formula: $
ho = \frac{60\ \text{g}}{3\ \text{cm}^3}$.

Step3: Calculate density

$\frac{60}{3}=20$, so the density is $20\ \text{g/cm}^3$.

Second Calculation (Mass = 72g, Volume = 8cm³)

Step1: Recall density formula

$
ho = \frac{m}{V}$.

Step2: Substitute values

Substitute $m = 72\ \text{g}$ and $V = 8\ \text{cm}^3$: $
ho = \frac{72\ \text{g}}{8\ \text{cm}^3}$.

Step3: Calculate density

$\frac{72}{8}=9$, so density is $9\ \text{g/cm}^3$.

Third Calculation (Density = 7 g/cm³, Volume = 9cm³)

Step1: Rearrange density formula for mass

From $
ho = \frac{m}{V}$, we get $m=
ho\times V$.

Step2: Substitute values

Substitute $
ho = 7\ \text{g/cm}^3$ and $V = 9\ \text{cm}^3$: $m = 7\ \text{g/cm}^3\times9\ \text{cm}^3$.

Step3: Calculate mass

$7\times9 = 63$, so mass is $63\ \text{g}$.

Fourth Calculation (Density = 11 g/cm³, Volume = 6cm³)

Answer:

s:

• First: $20\ \text{g/cm}^3$
• Second: $9\ \text{g/cm}^3$
• Third: $63\ \text{g}$
• Fourth: $66\ \text{g}$
• Fifth: $7\ \text{cm}^3$
• Sixth: $20\ \text{cm}^3$