Question

1. the voltage at point 1 equals

a 2 v
b 6 v
c 9 v
d 10 v
15 v
r1 2 kω
r2 3 kω
rx 10 kω
rs 5 kω
1
2

Explanation:

Step1: Calculate total resistance in series part

Resistors $R1 = 2k\Omega$ and $R2=3k\Omega$ are in series. The total resistance $R_{total1}=R1 + R2=2k\Omega+3k\Omega = 5k\Omega$.

Step2: Use voltage - division rule

The voltage - division rule for two - resistors in series is $V_x=\frac{R_x}{R_{total}}V_{source}$. Here, the source voltage $V = 15V$, and we want to find the voltage across $R2$.
$V_1=\frac{R2}{R1 + R2}\times V=\frac{3k\Omega}{2k\Omega+3k\Omega}\times15V$.
$V_1=\frac{3}{5}\times15V = 9V$.

Answer:

C. 9 V