Question

weight change

week	1	2	3	4	5
change (pounds)	0.3	- 0.86	1.02	-\frac{1}{4}	0.18

which list shows the data in order from least to greatest?
a - 0.86 -\frac{1}{4} 0.18 0.3 1.02
b -\frac{1}{4} - 0.86 0.18 0.3 1.02
c 0.18 -\frac{1}{4} 0.3 - 0.86 1.02
d 0.3 - 0.86 -\frac{1}{4} 0.18 1.02
use the data set listed to find the following values. 6, 10, 4, 16, 8, 6, 12, 14
25 mean =
26 median =
27 mode =
28 range =
29 iqr =

Explanation:

Step1: Convert -1/4 to decimal

$- \frac{1}{4}=-0.25$

Step2: Compare negative numbers

Among -0.86 and -0.25, since $|-0.86| = 0.86$ and $|-0.25|=0.25$, and $0.86>0.25$, then -0.86 < -0.25.

Step3: Compare all numbers

The order from least to greatest is -0.86, -0.25, 0.18, 0.3, 1.02.

(for 25 - 29):

Step1 (for mean - 25):

Sum of data: $6 + 10+4 + 16+8+6+12+14=76$. Number of data points $n = 8$. Mean $\bar{x}=\frac{76}{8}=9.5$

Step2 (for median - 26):

Arrange data in ascending order: 4, 6, 6, 8, 10, 12, 14, 16. Since $n = 8$ (even), median $=\frac{8 + 10}{2}=9$

Step3 (for mode - 27):

The number 6 appears 2 times, more frequently than other numbers, so mode = 6

Step4 (for range - 28):

Range = Maximum - Minimum. Maximum = 16, Minimum = 4. Range $=16 - 4=12$

Step5 (for IQR - 29):

First - quartile ($Q_1$): For the lower half 4, 6, 6, 8, $Q_1=\frac{6+6}{2}=6$. Third - quartile ($Q_3$): For the upper half 10, 12, 14, 16, $Q_3=\frac{12 + 14}{2}=13$. IQR=$Q_3 - Q_1=13 - 6 = 7$

Answer:

A. -0.86, $-\frac{1}{4}$, 0.18, 0.3, 1.02