Question

what is the change in heat of a 5.57 - kilogram block of aluminum when its temperature increases from - 28°c to - 19°c?
the specific heat of aluminum is 0.897 j/g°c.
round your answer to the correct number of significant figures.

joules

complete the sentence.

this process is endothermic because heat is absorbed by the aluminum.

Explanation:

Step1: Convert mass to grams

$m = 5.57\ kg\times1000 = 5570\ g$

Step2: Calculate temperature change

$\Delta T=- 19^{\circ}C-(-28^{\circ}C)=9^{\circ}C$

Step3: Use heat - change formula

The formula for heat change is $Q = mc\Delta T$, where $c = 0.897\ J/g^{\circ}C$, $m = 5570\ g$ and $\Delta T=9^{\circ}C$.
$Q=5570\times0.897\times9$
$Q = 5570\times8.073$
$Q = 45066.61\ J$
Rounding to three significant figures (since 0.897 has three significant figures), $Q = 45100\ J$

Answer:

45100