Question

what common ratio is being solved for in the exponential function $f(x) = 100(1.25)^{x - 3}$? (1 point) the common ratio in the equation is \boxed{}. check answer remaining attempts : 3

Explanation:

Step1: Recall exponential function form

The general form of an exponential function is \( f(x) = a(b)^{x - h}+k \) (or simpler form \( f(x)=a(b)^x \) when \( h = 0,k = 0 \)), where \( b \) is the common ratio (or base) for exponential growth/decay.

Step2: Identify the base in given function

In the function \( f(x)=100(1.25)^{x - 3} \), comparing with the general form, the base (common ratio) is the value raised to the power of \( (x - 3) \), which is \( 1.25 \).

Answer:

\( 1.25 \)