Question

what is the conditional relative frequency of having more than one dog, given there is a flea infestation? round your answer to the nearest thousandths place.

Explanation:

Step1: Recall conditional - relative - frequency formula

The formula for conditional relative frequency is $P(A|B)=\frac{P(A\cap B)}{P(B)}$. In terms of a two - way frequency table, if we want to find the conditional relative frequency of having more than one dog given there is a flea infestation, we use the value in the cell corresponding to "Has more than one dog" and "Has Flea Infestation" divided by the row total of "Has Flea Infestation".

Step2: Identify relevant values from the table

The value in the cell for "Has more than one dog" and "Has Flea Infestation" is $0.032$, and the row total for "Has Flea Infestation" is $0.069$.

Step3: Calculate the conditional relative frequency

$P(\text{more than one dog}|\text{flea infestation})=\frac{0.032}{0.069}\approx0.464$

Answer:

$0.464$