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in $\\triangle abc, m\\angle a = 73^{\\circ}; m\\angle b = 41^{\\circ}$…

Question

in $\triangle abc, m\angle a = 73^{\circ}; m\angle b = 41^{\circ}$. what is $m\angle c$? enter your answer in the box.

Explanation:

Step1: Recall triangle angle sum rule

The sum of angles in a triangle is $180^\circ$, so $m\angle A + m\angle B + m\angle C = 180^\circ$.

Step2: Substitute known angle values

Substitute $m\angle A=73^\circ$, $m\angle B=41^\circ$:
$73^\circ + 41^\circ + m\angle C = 180^\circ$

Step3: Calculate sum of known angles

$73^\circ + 41^\circ = 114^\circ$

Step4: Solve for $m\angle C$

$m\angle C = 180^\circ - 114^\circ$

Answer:

$66^\circ$