Question

what is the equation of the line that passes through the point (4, -4) and has a slope of -3? answer attempt 2 out of 2 y = 3x + 8 submit answer

Explanation:

Step1: Recall point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope of the line.
Here, $x_1 = 4$, $y_1=-4$ and $m=-3$.

Step2: Substitute values into point - slope form

Substitute $x_1 = 4$, $y_1=-4$ and $m = - 3$ into $y - y_1=m(x - x_1)$:
$y-(-4)=-3(x - 4)$
Simplify the left - hand side: $y + 4=-3(x - 4)$

Step3: Expand and simplify

Expand the right - hand side: $y+4=-3x + 12$
Subtract 4 from both sides: $y=-3x+12 - 4$
Simplify: $y=-3x + 8$

Answer:

$y=-3x + 8$