Question

what is the greatest possible integer value of x for which $sqrt{x-5}$ is an imaginary number?○ 3○ 4○ 5○ 6

Explanation:

Step1: Define imaginary square root condition

A square root $\sqrt{n}$ is imaginary when $n < 0$.

Step2: Set up inequality for the radicand

$x - 5 < 0$

Step3: Solve the inequality

$x < 5$

Step4: Find greatest integer x

The largest integer less than 5 is 4.

Answer:

B. 4