Question

what is the length of the guy wire of the telephone pole? 15 m 8 m

Explanation:

Step1: Identify right - triangle

The telephone pole, the ground, and the guy - wire form a right - triangle with legs of lengths 8 m and 15 m.

Step2: Apply Pythagorean theorem

The Pythagorean theorem for a right - triangle is $a^{2}+b^{2}=c^{2}$, where $a = 8$, $b = 15$, and $c$ is the length of the hypotenuse (the guy - wire). So $c=\sqrt{a^{2}+b^{2}}=\sqrt{8^{2}+15^{2}}$.

Step3: Calculate the value

First, calculate $8^{2}=64$ and $15^{2}=225$. Then $8^{2}+15^{2}=64 + 225=289$. And $\sqrt{289}=17$.

Answer:

17 m