Question

what is the magnitude of the electric field that must exist inside a 2.00 cm long, 220 ω resistor if 1.00 a of current flows through it? kv/m.

Explanation:

Step1: Calculate the potential difference across the resistor

Use Ohm's law $V = IR$. Given $I = 1.00\ A$ and $R=220\ \Omega$, so $V=1.00\times220 = 220\ V$.

Step2: Calculate the electric - field magnitude

The formula for the electric field $E=\frac{V}{d}$. The length of the resistor $d = 2.00\ cm=0.02\ m$ and $V = 220\ V$. Then $E=\frac{220}{0.02}=11000\ V/m = 11\ kV/m$.

Answer:

$11\ kV/m$